Credibility of a Single Car - Bailey & Simon Flashcards

1
Q

Experience Rating Formula

A

[(# of claims in group) / (earned premium in group at present 0 yrs. claim-free rates)] / [(# of claims in class) / (earned premium in class at present 0 yrs. claim-free rates)]

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2
Q

Calculating the Mod

A

Mod = ZR + (1-Z) Z = credibility R = ratio of actual losses to expected losses

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3
Q

Calculating R

A

Years claim-free & R

1+ : 0

0 : 1 / (1 - e^-lambda) where lambda = # of claims from class / earned car years of insureds in class

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4
Q

When to use a premium base for frequency

A

Hazam states that a premium base only eliminates maldistribution if:

  1. High frequency territories are also high average premium territories.
  2. Territorial (rate) differentials are proper.
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5
Q

Poisson formula

A

Pr(X = k) = (lambdak * e-lambda) / k!

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6
Q

Conclusions of paper

A
  1. The experience of a single car for 1 year has significant and measurable credibility for experience rating.
  2. Individual risk experience is more credible when there is more variance in loss experience within a risk class, which occurs in less refined risk classification systems.
  3. The credibilities for varying years of experience should increase in proportion to the # of years of experience.
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7
Q

Credibility for 2 and 3 years of experience relative to 1 year

A

The credibility increases in proportion to the # of years only for low credibilities. The closer the credibilities for 2 and 3 years of experience are to 2 and 3 times the 1 year credibility, then the less variation in insured’s probability of an accident. This could be due to:

  1. Less risks entering/exiting the portfolio.
  2. Risk characteristics not changing much over time.
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8
Q

Bühlmann Credibility

A

Suppose X is a random variable with some distribution with parameter OMEGA, and OMEGA itself is a random variable with some distribution and additional parameters. In that case, the credibility of a sample of n observations from X is given by:

Z = n / (n+k)

n = # of claims in sample

k = E[Var(X|OMEGA)] / Var(E[X|OMEGA])

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