Chapter 27.1 Flashcards

(22 cards)

1
Q

amine suffix

A

–amine

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2
Q

amine prefix

A

alkyl

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3
Q

If there is another priority
functional group as well
as the amine group or the nh2 is not at the end of the chain

A

prefix of amino is used

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4
Q

primary amines with more than one nh2

A

prefix: di, tri, etc amino
suffix: longest chain

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5
Q

secondary and tertiary amines with the same -r group

A

prefix: di, tri alkyl
suffix: amine

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6
Q

secondary and tertiary amines with the different-r group

A

give longest chain suffix amine
shorter chains as N prefixes in alphabetical order

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7
Q

Primary aliphatic amines act as Bronsted-Lowry Bases because

A

lone pair of electrons on the nitrogen form a
dative covalent bond with a H+ and so accepting a proton.

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8
Q

Primary aliphatic amines are stronger bases than ammonia because

A

alkyl groups release and push electrons towards the nitrogen atom and so make it a stronger base.

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9
Q

why don’t primary aromatic amines e.g. phenylamine form basic solutions?

A

because the lone pair of electrons on the nitrogen delocalise with the ring of electrons in the benzene ring. n is less able to accept protons

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10
Q

Give the order of base strength from weaker to stronger bases.

A
  • Aromatic amines
  • Ammonia
  • Primary amines
  • Tertiary amines
  • Secondary amines.
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11
Q

What do amines react with acids to form?

A

Ammonium salts.

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12
Q

What does the addition of NaOH to the ammonium salt do?

A

Will convert it back to the amine.

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13
Q

Give a reaction of a primary amine with an acid.

A

CH₃NH₂+H⁺→CH₃NH₃⁺

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14
Q

Give a reaction of a secondary amine with an acid.

A

(CH₃CH₂)₂NH+H⁺→(CH₃CH₂)₂NH₂⁺

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15
Q

Give a reaction of a tertiary amine with an acid.

A

(CH₃CH₂)₃N -> (CH₃CH₂)₃NH⁺

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16
Q

Primary amines can be formed by the—- reaction between haloalkanes and
ammonia

A

nucleophilic substitution

16
Q

ionic salt formed from amine and acid show that compounds are acid soluble, for example

A

e.g. Phenylamine is not very soluble in water but phenylammonium chloride is soluble

17
Q

Reaction with ammonia and haloalkane forming primary amine

A

Excess ammonia dissolved in ethanol is the reagent
1. nucleophile attacks the haloalkane to form an intermediate
2. a second ammonia removes a proton from the
intermediate (acts as base) to form the
amine.

18
Q

Using an excess of ammonia can limit further substitution
reactions and

A

will maximise the amount of primary amine
formed

19
Q

A primary amine will react with a haloalkane to form

A

a secondary amine

20
Q

secondary amine will react with a haloalkane to form

A

a tertiary amine.

21
Q

Reducing nitroarenes(-NO2) to aromatic amines(-NH2)

A

nitro group reduced to an amine group
Reagent: Sn and concentrated HCl
Conditions: Heating
Mechanism: reduction