Method Parameters

Question 1

What is “out” parameter modifier used for?

Answer 1

The “out” keyword causes arguments to be passed by reference.

Question 2

What are 2 differences between “out” and “ref” parameter modifiers?

Answer 2

When using “ref” you must initialize the variable that you will be passing. When using “out” you do not have to initialize the variable you will be passing.

Question 3

What will be shown in Console?

class MyClass
{
    private void MyMethod(out int myVar)
    {
        string aWord = "Hello";
        Console.Write(aWord);
    }

int myInt = 5;
MyMethod(out myInt);
Console.Write(myInt); }

Answer 3

This code will not compile. The method parameter marked with “out” keyword must be assigned the value before control leaves that method.

This will result in compile time error:
“The out parameter ‘myVar’ must be assigned to before control leaves the current method”

Question 4

Will this compile?

class ExampleClass
{
    public void SampleMethod(out int i) { }
    public void SampleMethod(ref int i) { }
}

Answer 4

No, this will not compile. “ref” and “out” modifiers are not considered part of the method signature at compile time.

Question 5

Like “ref”, “out” parameter is passed by reference. True or false?

Answer 5

True.