State the primary trigonometric ratios for an acute angle θ in a right triangle.
sin θ = opposite/hypotenuse, cos θ = adjacent/hypotenuse, tan θ = opposite/adjacent
Solve for θ if sin θ = 0.6, where 0° ≤ θ ≤ 90°.
θ = sin⁻¹(0.6) ≈ 36.87°
Solve for θ if cos θ = 0.3, 0° ≤ θ ≤ 360°.
θ = cos⁻¹(0.3) ≈ 72.54° or θ ≈ 360° - 72.54° = 287.46°
Solve for θ if tan θ = -1, 0° ≤ θ ≤ 360°.
θ ≈ 135° or θ ≈ 315° (quadrants II and IV where tan is negative)
Write the exact values of sin 30°, cos 45°, and tan 60°.
sin 30° = 1/2, cos 45° = √2/2, tan 60° = √3
State the CAST rule.
Quadrant I: all trig ratios positive, Quadrant II: sin positive, Quadrant III: tan positive, Quadrant IV: cos positive
Determine the amplitude, period, phase shift, and vertical displacement for y = 3sin(2x - 90°) + 4.
Amplitude = 3, Period = 360°/2 = 180°, Phase shift = 90°/2 = 45° right, Vertical displacement = 4 up
Graph y = cos x for 0° ≤ x ≤ 360°. Identify key points.
Key points: (0°, 1), (90°, 0), (180°, -1), (270°, 0), (360°, 1)
Determine the general solution for sin θ = 0.5.
θ = 30° + 360°n or θ = 150° + 360°n, n ∈ ℤ
Determine the general solution for cos θ = -√3/2.
θ = 150° + 360°n or θ = 210° + 360°n, n ∈ ℤ
Determine the general solution for tan θ = √3.
θ = 60° + 180°n, n ∈ ℤ
Solve 2sin²x - 1 = 0 for 0° ≤ x ≤ 360°.
sin²x = 1/2 → sin x = ±√(1/2) = ±√2/2 → x = 45°, 135°, 225°, 315°
Prove the identity: (1 + tan²x) = sec²x.
Divide both sides of sin²x + cos²x = 1 by cos²x: tan²x + 1 = sec²x ✔
Prove the identity: sin x cos x = (1/2)sin 2x.
Double-angle identity: sin 2x = 2 sin x cos x → sin x cos x = (1/2) sin 2x ✔
Solve cos 2x = 0.5 for 0° ≤ x ≤ 360°.
2x = 60° or 300° → x = 30° or 150°
Write the double-angle identity for cos 2x in three forms.
cos 2x = cos²x - sin²x = 2cos²x - 1 = 1 - 2sin²x
Solve 2sin x + √3 = 0 for 0° ≤ x ≤ 360°.
sin x = -√3/2 → x = 240°, 300° (quadrants III and IV where sin is negative)
Sketch y = 2cos(3x) on 0° ≤ x ≤ 360°.
Amplitude = 2, Period = 360°/3 = 120°, 3 cycles occur in 0°–360°
Determine the exact solution for sin 3x = 0 on 0° ≤ x ≤ 360°.
3x = 0°, 180°, 360° → x = 0°, 60°, 120°
Use the sine law to solve for ∠C given a = 10, b = 7, ∠A = 40°.
sin C / c = sin A / a → sin C = c × sin A / a → calculate numeric solution as needed
Use the cosine law to solve for side c given a = 8, b = 6, ∠C = 120°.
c² = a² + b² - 2ab cos C → c² = 64 + 36 - 2(8)(6)(cos 120°) = 100 - (-48) = 148 → c ≈ 12.17
Determine all solutions for cos x = 0 in the interval 0° ≤ x ≤ 360°.
x = 90°, 270°
Solve the equation tan²x - 3 = 0, 0° ≤ x ≤ 360°.
tan²x = 3 → tan x = ±√3 → x = 60°, 120°, 240°, 300°
Simplify sin x / cos x.
tan x