24.5 redox and qualitative analysis Flashcards

(13 cards)

1
Q

what is the redox reaction between Fe2+ and MnO4 - in acid conditions used for?

A

a basis for a redox titration

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2
Q

in Fe2+ and MnO4 - reaction what happens?

A

Fe2+ is oxidised to Fe3+
MnO4 - is reduced to Mn2+

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3
Q

equation for Fe2+ and MnO4- and colour change

A

MnO4 - + 8H+ + 5Fe2+ —> Mn2+ + 5Fe3+ + 4H2O
purple —-> colourless

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4
Q

equation for Fe3+ and I- and colour change

A

2Fe3+ + 2I- —–> 2Fe2+ + I2
orange-brown —-> pale-green + brown
colour change is obscured by iodine’s brown colour

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5
Q

what happens in the reaction between Fe3+ and I-?

A

Fe3+ is reduced to Fe2+
I- is oxidised to I2

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6
Q

why is Fe2+ oxidised and MnO4 - reduced in the reaction?

A

electrode potential for MnO4-/Mn2+ is more positive than Fe2+/Fe3+

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7
Q

equation for reaction of Cr2O7 2- and Zn and colour change

A

Cr2O7 2- + 14H+ + 3Zn —-> 2Cr3+ + 7H2O + 3Zn2+
orange——> green

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8
Q

what happens if an excess of zinc is added to chromium III ions?

A

reduced further
Zn + 2Cr3+ —–> Zn2+ + 2Cr2+
green—–> pale blue

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9
Q

equation for hydrogen peroxide and chromium III

A

3H2O2 + 2Cr3+ + 10OH- —–> 2CrO4 2- + 8H2O

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10
Q

what happens in reaction for for hydrogen peroxide and chromium III?

A

chromium is oxidised from +3 to +6
oxygen is reduced from -1 to -2

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11
Q

what happens when Cu2+ reacts with excess iodide ions?

A

I- is oxidised to brown iodine
Cu2+ is reduced to Cu+

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12
Q

what does Cu+ form after after being reduced when reacting with iodide ions?

A

a white precipitate of copper I iodide
2Cu2+ + 4I- —> 2CuI + I2
pale blue ——> white precipitate + brown

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13
Q

what happens when solid copper I oxide reacts with hot dilute sulphuric acid ?

A

brown precipitate of copper is formed together with a blue solution of copper II sulphate
Cu + has been simultaneously oxidised and reduced so disproportionation has occurred

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