what is the redox reaction between Fe2+ and MnO4 - in acid conditions used for?
a basis for a redox titration
in Fe2+ and MnO4 - reaction what happens?
Fe2+ is oxidised to Fe3+
MnO4 - is reduced to Mn2+
equation for Fe2+ and MnO4- and colour change
MnO4 - + 8H+ + 5Fe2+ —> Mn2+ + 5Fe3+ + 4H2O
purple —-> colourless
equation for Fe3+ and I- and colour change
2Fe3+ + 2I- —–> 2Fe2+ + I2
orange-brown —-> pale-green + brown
colour change is obscured by iodine’s brown colour
what happens in the reaction between Fe3+ and I-?
Fe3+ is reduced to Fe2+
I- is oxidised to I2
why is Fe2+ oxidised and MnO4 - reduced in the reaction?
electrode potential for MnO4-/Mn2+ is more positive than Fe2+/Fe3+
equation for reaction of Cr2O7 2- and Zn and colour change
Cr2O7 2- + 14H+ + 3Zn —-> 2Cr3+ + 7H2O + 3Zn2+
orange——> green
what happens if an excess of zinc is added to chromium III ions?
reduced further
Zn + 2Cr3+ —–> Zn2+ + 2Cr2+
green—–> pale blue
equation for hydrogen peroxide and chromium III
3H2O2 + 2Cr3+ + 10OH- —–> 2CrO4 2- + 8H2O
what happens in reaction for for hydrogen peroxide and chromium III?
chromium is oxidised from +3 to +6
oxygen is reduced from -1 to -2
what happens when Cu2+ reacts with excess iodide ions?
I- is oxidised to brown iodine
Cu2+ is reduced to Cu+
what does Cu+ form after after being reduced when reacting with iodide ions?
a white precipitate of copper I iodide
2Cu2+ + 4I- —> 2CuI + I2
pale blue ——> white precipitate + brown
what happens when solid copper I oxide reacts with hot dilute sulphuric acid ?
brown precipitate of copper is formed together with a blue solution of copper II sulphate
Cu + has been simultaneously oxidised and reduced so disproportionation has occurred